-4y^2+50y+600y=0

Solution for -4y^2+50y+600y=0 equation:

-4y^2+50y+600y=0

We add all the numbers together, and all the variables

-4y^2+650y=0

a = -4; b = 650; c = 0;
Δ = b2-4ac
Δ = 6502-4·(-4)·0
Δ = 422500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{422500}=650$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(650)-650}{2*-4}=\frac{-1300}{-8}
=162+1/2
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(650)+650}{2*-4}=\frac{0}{-8}
=0
$